Is there any reaction happens when calcium ion added to calcium hydroxide?

[Green18]

Silly question lol
But Is there any reaction if calcium ion added to calcium hydroxide?

If NaOH or any alkali is added to metal ions, insoluble metal hydroxide is formed.
So, what if weak alkali Calcium hydroxide is added to Calcium ion, what will it happen? Will it has no reaction just like it is added to ammonia solution with the reason of concentration of OH{-} in dilute ammonia is low? Or it becomes part of the calcium hydroxide?Or calcium hydroxide white percipitate will form?

 

[Borek]

Depends on the initial concentrations. Such a solution is described by the solubility product. Have you heard about it yet?

 

[Green18]

Depends on the initial concentrations. Such a solution is described by the solubility product. Have you heard about it yet?

Ummm no, haven't heard about it :(
It's about the initial concentration. Does it mean (let say we have Ca(OH)2 and CaCl2) if the Ca(OH)2 has a relative high concentration, then it can form insoluble Ca(OH)2?

 

[Borek]

Yes, you should be able to precipitate Ca(OH)₂ from the Ca(OH)₂ solution just by adding concentrated CaCl₂.

However, you can't have Ca(OH)₂ with a "relatively high concentration". Ca(OH)₂ is weakly soluble, below 2 g per 1L if memory serves me well.

 

[Green18]

I see :) Thank you so much! :)

 

[Green18]

Yes, you should be able to precipitate Ca(OH)₂ from the Ca(OH)₂ solution just by adding concentrated CaCl₂.

However, you can't have Ca(OH)₂ with a "relatively high concentration". Ca(OH)₂ is weakly soluble, below 2 g per 1L if memory serves me well.

Uh! But …since the concentration of Ca(OH)2 can't be high, than its concentration of OH- (aq) ions in dil. Ca(OH)2 must be low, then, wouldn't it have the same situation as it reacts with dil aqueous ammonia, and does not give precipitate?

 

[Borek]

No, that's a different situation. You mentioned "diluted ammonia", I have specifically called for concentrated CaCl₂.

Doesn't mean concentrated ammonia will be able to precipitate Ca(OH)₂. It is rather easy to calculate, but using theory that you don't know yet.

 

[Green18]

Ohh (facepalm) sorry for my misunderstanding. Ok, i will let go of it then :p