Is this a reasonable approach to calculating pressure difference?

Click For Summary
SUMMARY

The discussion centers on calculating the pressure difference between two points in a fluid system involving glycerol, air, and water. The user initially calculated pressures at points A and B using the formula P2-P1=ρ2gh2 - ρ1gh1, resulting in a pressure difference of 11,200 Pa. However, subsequent responses clarified that the calculations for both points A and B were incorrect due to misinterpretation of the problem statement, particularly regarding the reference points for pressure calculations.

PREREQUISITES
  • Understanding of fluid mechanics principles, specifically hydrostatic pressure.
  • Familiarity with the pressure difference formula: P2-P1=ρ2gh2 - ρ1gh1.
  • Knowledge of specific gravity and density of fluids, particularly glycerol and water.
  • Ability to interpret fluid system diagrams and identify reference points for pressure calculations.
NEXT STEPS
  • Review hydrostatic pressure calculations in fluid mechanics.
  • Study the concept of reference heights in pressure calculations.
  • Learn about the properties and applications of glycerol in fluid systems.
  • Examine examples of pressure difference calculations in multi-fluid systems.
USEFUL FOR

Students studying fluid mechanics, engineers working with fluid systems, and anyone involved in pressure measurement and analysis in multi-phase fluids.

ana111790
Messages
41
Reaction score
0

Homework Statement


What is the pressure difference between points A and B (point where glycerol and air heads meet) in the picture, if d1 = 0.50 meters, d2 = 0.25 meters, and d3 = 0.71 meters and d4 = 0.86 meters. (ρH2O= 1.00 x 10^3 kg/m^3, ρgly = 1.25 x 10^3/m^3)

[PLAIN]http://img535.imageshack.us/img535/5260/pressureproblem.jpg

Homework Equations


I know that pressure difference can be found through
P2-P12gh2 - ρ1gh1

The Attempt at a Solution


I am confused because there are 3 different substances involved, glycerol, air and water.
What I did was I took the pressure at the bottom of the system to be the h0=0 (reference height) and calculated Pressure at A and Pressure at B independently and then subtracted them.

So:
Pressure at point A = ρH2O*g*d1 + ρglycerol*g*d2
Pressure at point A = (1000kg/m^3 * 9.8 m/s^2 * .5m) + (1250kg/m^3 * 9.8m/s * .25m)
Pressure at point A = 7960 Pa

Pressure at point B = ρglycerol*g*d2 + ρglycerol*g*d3 + ρglycerol*g*d4sin45
Pressure at point B = (1250kg/m^3 * 9.8m/s^2 * .25m) + (1250kg/m^3 * 9.8m/s * .71m) + (1250kg/m^3 * 9.8m/s^2 *.86m*sin45)
Pressure at point B = 19200 Pa

Pressure difference = Pressure at point B - Pressure at point A
Pressure difference = 11200 Pa

Does this seem like a reasonable approach and answer?
Thanks!
 
Last edited by a moderator:
Physics news on Phys.org
please clarify which are the points A and B.
 
I took point A to be where distance d1 starts, along the the H2O head as nothing is mentioned in the problem statement about it.

Point B is explained in the problem as "point where glycerol and air heads meet".

Thank you.
 
If you consider point A to be where distance d1 starts, then your calculation of pressure at A is incorrect. It would not depend on glycerine column d2, it would just be equal to the pressure of H2O inside the container, which is unknown.

Also, the pressure at B would be equal to pressure of air in container, and not what you calculated, which is also unknown.
 
I think the questions is not clear. It would most probably be right to consider point A as the point where d2 ends at the bottom, that is, the lower point of (d1 + d2). In that case we can calculate pressure difference.
 
hmm. In the picture there is a lower case "a" where the H2O head meets the tube with H2O, and a lower case b where the air head meets the tube with air. Not sure if that is relevant.
I calculated those values relative to an arbitrary h0 which I chose to be at the very bottom of the system, so point A is higher than my h0 but point B is even higher.

This question is very confusing.
 
Can anyone help with this question?
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
914
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 10 ·
Replies
10
Views
9K
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K