Pressure Difference: F=10 Tonnes, A=100 sq m - Calculate & Understand

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Homework Help Overview

The discussion revolves around understanding pressure differences affecting a ceiling, specifically in the context of a scenario where a ceiling may lift due to external wind pressure. The problem involves calculating forces based on given pressure differences and understanding the implications of these forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of pressure differences on the ceiling, questioning which side experiences greater pressure during windy conditions. They also discuss the meaning of "a lift of 10 tonnes" and how to calculate the corresponding forces using the equation p=F/A. Some participants express confusion regarding normal air pressure and its relation to the problem.

Discussion Status

Participants are actively engaging with the problem, clarifying concepts and attempting calculations. Some have provided guidance on understanding pressure dynamics, while others are working through the mathematical aspects of the problem. There is a recognition of the need to consider net forces in the context of the ceiling's stability.

Contextual Notes

Participants note the lack of specific information regarding normal air pressure values and express uncertainty about how to apply the given equation effectively. The original poster indicates reliance on textbook information that may be insufficient for solving the problem.

Kolika28
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Homework Statement


[/B]
A ceiling can blow off due to pressure difference between the inside and outside of the house. In a magazine, it said: "Let's have a ceiling of 100 square meters. A pressure difference of 1% of the air pressure between the two sides of the ceiling is equivalent to a lift of 10 tonnes. We see that the ceiling should be properly fixed against being lifted up.

a) On which side of the ceiling is the air pressure the greatest when it blows heavily outside?
b) What can be meant by the phrase "a lift of 10 tonnes"?
c) Perform calculations that confirm the information in the text.
d) When it's windy out, it's a good idea to open air lanterns in the house. Why?


Homework Equations


p=F/A[/B]

The Attempt at a Solution


b) What can be meant by the phrase "a lift of 10 tonnes"?
F=ma=10 000kg*9,81m/s^2=98 100N≈100kN

Question b is the only one I get right. I don't know how to solve the rest because my book only tells me the equation p=F/A and does not have any more information about pressure.
Really appreciate some help :)
 
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I have some issues with the wording of the question but...

a) if the ceiling goes up/lifts is the pressure greater on the upper or lower surface of ceiling?

c) what is normal air pressure and what would 1% of that be?
 
Hi Kolika28 and welcome to PF.

You have not answered (a). It does not require an equation, just an understanding of pressure, and the answer is helpful to understanding how to use p = F/A and to answering the rest of the questions.
 
CWatters and Kuruman, thank you for your help! I think I understand it now. I am sorry for the wording of the question by the way if it caused some confusion!
a) If the ceiling goes up/lifts the pressure must be greater on the inside of the house, right?
c) Have to find 1% of 101, 3 kPa, which is 1013 Pa. Do I then have to add 1013Pa to 101,3kPa? And then calculate the force by putting the number in the equation like this:
101,3kPa+1013Pa=F/(100m^2)?
d) One should open the laterns to equalize the pressure?
 
(a) and (d) are correct. For (c) consider that you have a force pushing down and another force from the inside pushing up. If the two are equal, nothing happens. It's the net force that counts. What is the net force in this case?
 
Ohhh, of course. The net force is 1013Pa.
p=F/A
F=pA
F=1013Pa*100m^2

Thank you so much!
 

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