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Part (1) of this question posted in post 3. Is it a type-o or correct. Not looking for solution.

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- Thread starter anthonyk2013
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- #1

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Part (1) of this question posted in post 3. Is it a type-o or correct. Not looking for solution.

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- #2

Doug Huffman

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Yes, it appears to be so, from what I can see.

- #3

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- #4

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Forgot the image

- #5

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The integrals look ok so far.

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- #7

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Ya I differentiated the top and you get 12x-5 all over 12x-5.

- #8

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Ah I see. Could be a typo. But this integral should be solvable as well.

- #9

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Part 1&2 only worth 4% on exam paper. Seem like a but of work for 2%

- #10

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Private theories are not allowed in this forum. :D But don't worry here. Sorry, I can only look at the math.Part 1&2 only worth 4% on exam paper. Seem like a but of work for 2%

- #11

Mark44

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- #13

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That's are far as I got I had x-1.

- #14

Mark44

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Well, that's wrong. The first term in the quotient should by (1/2)x. See http://en.wikipedia.org/wiki/Polynomial_long_division.That's are far as I got I had x-1.

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- #15

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Ya silly mistake by me.

- #16

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Wondering the the solution the this question is right or wrong ?

Thanks

- #17

mfb

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Also, what happens if you differentiate your result? Do you get the initial fraction? This is often a very easy check you can always do if you are unsure.

The whole substitution is not helpful here. Posts 6 and 11 show the best approach.

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When studying on my own I divided the polynomial but the devision didn't look right. I'll attempt it again and post later. Thanks.

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- #20

mfb

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Looks right so far.

- #21

Mark44

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- #22

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Ill finish later. Too many kids around[emoji86]

- #23

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Thanks for the reminder mark44. Long time since i was in grade school as you call it

- #24

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Latest attempt. Wondered if I'm right.

- #25

mfb

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And check what you have in the denominators and logs - but I guess those are just typos.

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