Part (1) of this question posted in post 3. Is it a type-o or correct. Not looking for solution.
Yes, it appears to be so, from what I can see.
Forgot the image
What is a type-o? Or do you think it is a typo? Then type-o probably is a typo.
The integrals look ok so far.
Hint for part i): Try to rearrange ##6x^2-5x+3## into some polynome your can divide by ##12x-5## plus a constant.
Ya I differentiated the top and you get 12x-5 all over 12x-5.
Ah I see. Could be a typo. But this integral should be solvable as well.
Part 1&2 only worth 4% on exam paper. Seem like a but of work for 2%
Private theories are not allowed in this forum. :D But don't worry here. Sorry, I can only look at the math.
Anthonyk, why would you think the problem has a typo? This is an easy integral - just divide the numerator by the denominator.
Lecturer thinks it is because of the low mark. Looking back a previous exam papers made an assumption. If We are wrong I hold my hand up.
That's are far as I got I had x-1.
Well, that's wrong. The first term in the quotient should by (1/2)x. See http://en.wikipedia.org/wiki/Polynomial_long_division.
Ya silly mistake by me.
Wondering the the solution the this question is right or wrong ?
What happened in (4)? The denominators vanished?
Also, what happens if you differentiate your result? Do you get the initial fraction? This is often a very easy check you can always do if you are unsure.
The whole substitution is not helpful here. Posts 6 and 11 show the best approach.
This solution is from class. We were given a reason why that were moved but I can remember.
When studying on my own I divided the polynomial but the devision didn't look right. I'll attempt it again and post later. Thanks.
Looks right so far.
Separate names with a comma.