Is this calculation correct for v = 2πfA ?

[ElectricJesus]

Is this calculation correct for v = 2πfA ??

Homework Statement

Prove that maximum speed of a mass on a spring is given by 2πfA

Ac = Centripetal acceleration
r = radius
v = velocity
f = frequency
π = pi

Homework Equations

Ac = (v^2)/r
Ac = 4(π^2)r(f^2)

The Attempt at a Solution

If Ac = (v^2)/r
and Ac = 4(π^2)r(f^2)

then (v^2)/r = 4(π^2)r(f^2)

so v^2 = 4(π^2)(r^2)(f^2)
and v = 2πrf


Just wondering if there is something wrong with this calculation?

 

[PeterO]

Homework Statement

Prove that maximum speed of a mass on a spring is given by 2πfA

Ac = Centripetal acceleration
r = radius
v = velocity
f = frequency
π = pi

Homework Equations

Ac = (v^2)/r
Ac = 4(π^2)r(f^2)

The Attempt at a Solution

If Ac = (v^2)/r
and Ac = 4(π^2)r(f^2)

then (v^2)/r = 4(π^2)r(f^2)

so v^2 = 4(π^2)(r^2)(f^2)
and v = 2πrf


Just wondering if there is something wrong with this calculation?

Is this mass being rotated in a "horizontal" circle on the end of a spring, or bouncing up and down on the end of a spring [where A might be the Amplitude?]

 

[ElectricJesus]

I messed up bad, this is a waste how do i remove the thread?