Is this correct? Newton's second law related.

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
6 replies · 2K views
Questions999
Messages
151
Reaction score
0
On an object with a mass of 3 kg a single force F acts perpendicular to the speed of the object.The object moves in a circle with a radius of 2 meters and the period is 3 seconds.a) Find the acceleration. I have the formula T=2*pi*r/v ,I find v here and then in the formula a=v^2/2 I replace v.
b) Find the module of the force F.
I think that it is F=m*v^2/r - mg and I have all the data to find F.
 
Physics news on Phys.org
Elaia06 said:
On an object with a mass of 3 kg a single force F acts perpendicular to the speed of the object.The object moves in a circle with a radius of 2 meters and the period is 3 seconds.a) Find the acceleration. I have the formula T=2*pi*r/v ,I find v here and then in the formula a=v^2/2 I replace v.
Correct.

Elaia06 said:
b) Find the module of the force F.
I think that it is F=m*v^2/r - mg and I have all the data to find F.
Incorrect.
 
what is exactly incorrect ? :)

oh is it 0?the force?
 
Last edited:
Elaia06 said:
what is exactly incorrect ? :)

Maybe the force is equal to the tension?
If the object is rotated at the end of a rope in a circular path, then the force acting on it is the tension of the rope. For example if a car is driving circular track then the force is friction.
 
so now I have T*cosx=mg ..and I find T :) Thanks :D
 
Elaia06 said:
what is exactly incorrect ? :)

oh is it 0?the force?
Nope. Then it wouldn't be in circular motion at all.
 
Elaia06 said:
so now I have T*cosx=mg ..and I find T :) Thanks :D
Am I missing something here? What is module of a force? The force is simply F=m*v^2/r