A car travels along the perimeter of a vertical circle (radius = 0.25 km) at a constant speed of 30 m/s. What is the magnitude of the resultant force on the 60-kg driver of the car at the lowest point on this circular path?
1) 0.37 kN
2) 0.80 kN
3) 0.22 kN
4) 0.59 kN
5) 0.45 kN
a_centripetal = m (v^2/r)
The Attempt at a Solution
F=mg + ma_centripetal = m (g + a_centripetal) = 60 kg (9.8 m/s^2 + (30m/s)^2/(250m)) = 804N = 0.8kN
but the answer I got was different from the answer i got with the question which is 0.22kN
can someone please explain how is it 0.22kN?