Is this function continuous and differentiable?

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The function in question, defined as f(x) = (x^2 - 1)/(x - 1), is not continuous or differentiable at x = 1 due to the undefined nature of f(1), which results in a 0/0 form. Although the (x-1) term can be canceled, this does not change the fact that the original function is undefined at that point. The discussion highlights the importance of specifying a function's domain to properly assess continuity and differentiability. The book's answer is contested, with participants agreeing that the function's definition is inadequate without clarifying its domain. Ultimately, the function cannot be considered continuous or differentiable at x = 1.
  • #31
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  • #32
Mes chers messieurs, there is no need for such a sophisticated debate, which most likely confuse the OP.

One commonly speaks of discontinuities if a point in a graph is missing, regardless of the domain. This is necessary to investigate the various types of singularities. Whether this is correct in a strict logical sense, as a non defined location might as well be considered outside of consideration, is in the end completely meaningless and a matter for philosophers and maybe logicians, although I doubt the latter will be interested. It is the type of discussion which never ends and which won't lead anywhere, and it is the reason we canceled philosophy from the board.

So whoever feels right, let it be so. Thirty posts for such a simple question are definitely twenty-five too many.

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