Is this function injective, surjective, or both?

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SUMMARY

The function f(x) = (x+1)/(x+2) for x ≠ -2 and f(x) = 1 for x = -2 is both injective and surjective, thus bijective. The derivative f'(x) = 1/(x+2)² is positive for all x, confirming that the function is strictly increasing. The limits at both infinities approach 1, and the behavior around the vertical asymptote at x = -2 indicates that the function covers all real numbers without repetition, fulfilling the criteria for bijectivity.

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Homework Statement



The following function f is a function from R to R. Determine whether f is injective (one-to-one), surjective (onto), or both. Please give reasons.

Homework Equations



f(x) = (x+1)/(x+2) if x != -2
f(x) = 1 when x = 2

The Attempt at a Solution



f'(x) = 1/(x+2)2 > 0 for all x

and the limits at both infinities are 1 using l'hopital.

So the way I see it is the function grows from 1+ when x is a large negative, and then there's a horizontal assymptote at x = -2 so just before x = -2 f(x) tends to infinity and just after x = -2 the f(x) goes from negative infinity and gradually increases to 1. and then ofcourse at the point x = - 2 f(x) = 1 because that value has been forced in the definition.

So now by visualising the graph I have a strong suspicion that this function is bijective, but I have no idea how to prove it 'analytically'
 
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OK nevermind i figured it out. Is there a way to remove my original post? Or should I post my reasoning incase it could be helpful to others?
 
Last edited:
Usually the latter is preferred
 

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