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Isaaic and Blaise decide to race. They both start at the same position at the same time. Isaaic runs at 2 m/s but decides to take a 2 minute rest stop. Blaise runs at half the speed and still wins by 10 meters. How far did Blaise run?

I can use only these equations.

X = V_{avg}T

V_{avg}= (V_{f}- V_{i})/T

A = (V_{f}- V_{i})/T

V_{f}^{2}= V_{i}^{2}+ 2ax

X = V_{i}T + (1/2)at

This is as far as I've gotten.

X_{b}= (1m/s)T_{b}

Blaise's distance is equal to his average velocity times his time.

Blaise's time is equal to Isaaic's time + 120 seconds

X_{b}= (1m/s)(T_{i}+ 120s)

Blaise's distance is equal to Isaaic's distance + 10 meters

X_{i}+ 10m = (1m/s)(T_{i}+ 120s)

but now i have no idea what to do. Shouldn't they have given me the acceleration? If we assume the acceleration to be 0 and try to solve for T_{i}, you end up dividing by 0 which leads nowhere.

Am I just not seeing the solution or is this problem missing some information?

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# Homework Help: Is this homework question missing information?

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