B Is this identity containing the Gaussian Integral of any use?

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The discussion centers around a mathematical identity involving the Gaussian integral, specifically the expression x∫e^(-x^2) dx - ∫∫e^(-x^2) dx dx = e^(-x^2)/2. Participants question its usefulness, suggesting it resembles established techniques for evaluating Gaussian integrals. Concerns are raised about notation clarity, particularly the repeated use of 'x' and potential sign errors in the identity. Some contributors note that similar identities can be generalized through partial integration and variable changes. Overall, the identity appears to lack practical application in its current form.
MevsEinstein
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What the title says
I found this identity: ##x\int e^{-x^2} dx - \int \int e^{-x^2} dx dx = e^{-x^2}/2## by solving the integral of ##x*e^{-x^2}## and then finding its integration-by-parts equivalent. Is this identity useful at all?
 
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MevsEinstein said:
Summary:: What the title says

I found this identity: ##x\int e^{-x^2} dx - \int \int e^{-x^2} dx dx = e^{-x^2}/2## by solving the integral of ##x*e^{-x^2}## and then finding its integration-by-parts equivalent. Is this identity useful at all?
IMO, no. Unless I'm missing something, this looks similar to the integral ##\int_{-\infty}^\infty e^{-x^2}dx## is evaluated. IOW, by instead looking at the double integral. I'd bet this technique is in most calculus textbooks, although usually as the integral ##\int_{-\infty}^\infty \int_{-\infty}^\infty e^{(-x^2 - y^2)/2}dy dx##.
 
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Fix notation. Using 'x' too much. For example dxdx?
 
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Mark44 said:
IMO, no. Unless I'm missing something, this looks similar to the integral ##\int_{-\infty}^\infty e^{-x^2}dx## is evaluated. IOW, by instead looking at the double integral. I'd bet this technique is in most calculus textbooks, although usually as the integral ##\int_{-\infty}^\infty \int_{-\infty}^\infty e^{(-x^2 - y^2)/2}dy dx##.
There aren't any infinities in the formula.
 
mathman said:
Fix notation. Using 'x' too much. For example dxdx?
I don't know how to fix that problem. I'm still 13.
 
MevsEinstein said:
I don't know how to fix that problem. I'm still 13.
Use different letters for different things.
 
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MevsEinstein said:
I found this identity: ##x\int e^{-x^2} dx - \int \int e^{-x^2} dx dx = e^{-x^2}/2## by solving the integral of ##x*e^{-x^2}## and then finding its integration-by-parts equivalent. Is this identity useful at all?
Should read
##x\int e^{-x^2} dx - \int \int e^{-y^2} dydx = -e^{-x^2}/2## looks like also a sign error.
These "identities" can be generalized to many functions, its just partial integration and change of variables, for instance consider xsin(x2)
 
$$\int xe^{-x^2}dx=-e^{-x^2}/2$$.
 
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drmalawi said:
looks like also a sign error.
I couldn't edit the OP.
 

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