Is V0 the Voltage Drop Across R1 or R2 in a Voltage Divider?

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SUMMARY

In a voltage divider circuit, V0 is definitively the voltage drop across resistor R2, not R1. This conclusion is based on the conventional flow of current from the positive terminal to the negative terminal of the battery. The connection from the negative terminal to the bottom of R2 is considered to be at zero volts, reinforcing that V0 corresponds to the voltage across R2. Understanding this concept is crucial for accurately analyzing voltage dividers in electrical circuits.

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tylerc1991
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Homework Statement



This is more of a theoretical question than an actual numerical problem (so mods please move if this is in the wrong place).

The circuit below was copied from my book. Ultimately we are discussing the voltage divider. The book goes on to say that V0 is the voltage drop across R2. But I thought that conventional current flows from the positive terminal to the negative terminal. This would mean that V0 is the voltage drop across R1, right? Is it the voltage drop I have confused or the voltage divider? or both? Thank you for your help anyone!

Circuit_1.jpg
 
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The conductor connecting the negative terminal of the battery with the bottom of R2 is commonly considered to be at zero Volts. Thus, V0 is equal to the voltage dropped across R2.
 

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