sana2476 Messages 33 Reaction score 0 Thread starter Apr 9, 2009 #1 Let x not equal to zero be a vector in the nullspace of A. Then x is an eigenvector of A. I'm not sure how to start this proof
Let x not equal to zero be a vector in the nullspace of A. Then x is an eigenvector of A. I'm not sure how to start this proof
JG89 Messages 724 Reaction score 1 Apr 9, 2009 #2 If x is a non-zero vector in the null space of A, then you know that A is singular, and you also know that [tex]\lambda = 0[/tex] is an eigenvalue of A since A is invertible if and only if zero is not an eigenvalue of A. That should start you off.
If x is a non-zero vector in the null space of A, then you know that A is singular, and you also know that [tex]\lambda = 0[/tex] is an eigenvalue of A since A is invertible if and only if zero is not an eigenvalue of A. That should start you off.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Apr 9, 2009 #3 Saying that x is in the null space of A means that Ax= 0= 0x.