Is x in the nullspace of A an eigenvector of A?

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Let x not equal to zero be a vector in the nullspace of A. Then x is an eigenvector of A.


I'm not sure how to start this proof
 
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If x is a non-zero vector in the null space of A, then you know that A is singular, and you also know that [tex]\lambda = 0[/tex] is an eigenvalue of A since A is invertible if and only if zero is not an eigenvalue of A. That should start you off.
 
Saying that x is in the null space of A means that Ax= 0= 0x.