Is (x+sqrt(2)) or (-x+sqrt(2)) rational?

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SUMMARY

The discussion centers on proving that for each real number x, either (x + √2) or (-x + √2) is irrational. It is established that since √2 is irrational, the sum of a rational number and an irrational number results in an irrational number. The proof by contradiction is initiated by assuming that either expression is rational, leading to the conclusion that x must also be irrational, thereby confirming the original statement.

PREREQUISITES
  • Understanding of irrational numbers, specifically √2
  • Familiarity with proof by contradiction techniques
  • Basic algebraic manipulation involving rational numbers
  • Knowledge of properties of rational and irrational numbers
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This discussion is beneficial for students studying real analysis, mathematics educators, and anyone interested in understanding the properties of irrational numbers and proof techniques.

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Homework Statement



Prove that for each real number x, (x+sqrt(2)) is irrational or (-x+sqrt(2)) is irrational.


Homework Equations



We have already proven sqrt(2) is irrational
and a rational+an irrational=irrational.


The Attempt at a Solution



Proof by contradiction.

Assume (x+sqrt(2)) or (-x+sqrt(2)) is rational.

First set (x+sqrt(2))=(m/n) for some integers m and n.

I get stuck here at where to go with the contradiction.
 
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so say the positive sum is rational
x+sqrt{2} = \frac{p}{q} [\tex]<br /> <br /> then what is x? try using it to substitute into the negative sum
 
x=sqrt(2)

so...

2(sqrt(2))=(m/n)

I think I can take it from here. Thanks!
 

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