Is Your Vector Part of the Matrix's Solution Space?

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SUMMARY

The discussion focuses on determining whether a vector x is part of the solution space of a matrix M, specifically addressing the homogeneous equation Mx = 0. The matrix M provided is a 4x5 matrix, and the vectors v1 and v2 are both [1 0 0 1 1]T. The conclusion reached is that v1 is not in the solution space of M, as the multiplication M*v1 does not yield the zero vector. The conversation also highlights the importance of correctly interpreting the term "solution space," emphasizing that it typically refers to the null space when b is equal to zero.

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Homework Statement


a)Let M be a m*n matrix and x be a n*1 coordinate vector. How can you check whether or not x is in the solution space of M?

[0 1 1 1 0]
M=[1 1 0 0 1]
[0 1 1 0 1]
[1 0 1 0 0]

b)To decide whether or not the following are in the solution space of M
i) v1=[1 0 0 1 1]T ii) v2=[1 0 0 1 1]T
*T means the transpose of the matrices

Any help is appreciated


Homework Equations



{x[itex]\in[/itex]ℝn:Ax=0}

The Attempt at a Solution



I started by solving the homogeneous linear equation:
M*v1=0

[0 1 1 1 0]
[1 1 0 0 1]*[0 1 0 1 1]T = 0
[0 1 1 0 1]
[1 0 1 0 0]

[2 2 2 0]T ≠ 0

∴ v1 is not in the solution space of M

Am i doing the right here??
 
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What, exactly, was the wording of the question? To ask about the "solution space" of just a matrix, M, makes no sense. We talk about the "solution space" of an equation like "Mx= b" and the answer depends on b as well as M. The solution space of "Mx= 0", with b specfically equal to 0, is the "null space" or "kernel" of matrix M.

Yes, to determine whether a given vector, x, is in the solution space of Mx= b, simply multiply M and the given x and see if the result is equal to b. Assuming that the problem is really asking whether the given x is in the "null space", so that b= 0, it is immediately clear that the top row times x does not give 0 and so x is not in the null space.

But I am still concerned about the wording of the question. If it really said "solution space", it is possible that there is some non-zero "b", perhaps given in a previous part of the problem, that you missed.
 

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