(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

G is isomorphic to H.

Prove that if G has a subgroup of order n, H has a subgroup of order n.

2. Relevant equations

G is isomorphic to H means there is an operation preserving bijection from G to H.

3. The attempt at a solution

I don't know if this is the right approach, but

G has a subgroup of order n implies e is in the subgroup, and since e in G maps to e in H, e is in the potential new subgroup of H.

Suppose g is an element in the subgroup of G. Then, g maps to some h in the new subgroup of H.

Man, I think I'm proving the wrong thing here. I'm heading toward proving a subgroup in H, not that the order is the same. I need a new direction. Any one have a direction idea?

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# Homework Help: Isomorphic groups G and H, G has subgroup order n implies H has subgroup order n

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