Isomorphism between Q[x]/(x-1) and Q[x]/(x-2)

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Palindrom
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I really don't want to define a homomorphism like
psi(p(x))=p(x-1+I
I'm looking for another way to solve that next question:

Show that Q[x]/(x-1) is isomorphic to Q[x]/(x-2).
Any ideas?
Thanks in advance.
 
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You could show they're both isomorphic to a third ring...
 
Hurkyl said:
You could show they're both isomorphic to a third ring...
Of course, they're both isomorphic to Q... I really shouldn't do HW at 11 pm... Thanks!