Isomorphism of dihedral with a semi-direct product

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SUMMARY

The discussion centers on proving the isomorphism between the dihedral group \(D_m\) and the semi-direct product \(\mathbb{Z}_m \rtimes_{\varphi} \mathbb{Z}_2\) for \(m \geq 3\). The key elements include the cyclic nature of the groups involved, where \(\langle s \rangle \cong \mathbb{Z}_2\) and \(\langle r \rangle \cong \mathbb{Z}_m\). The proof requires understanding the normal subgroup properties of \(\langle r \rangle\) within \(D_m\) and the action of \(\varphi\) on the elements of \(\mathbb{Z}_m\). The discussion emphasizes the importance of defining \(\varphi\) correctly to establish the isomorphism.

PREREQUISITES
  • Understanding of group theory concepts, particularly dihedral groups.
  • Familiarity with semi-direct products and their properties.
  • Knowledge of cyclic groups and their structure.
  • Basic understanding of group actions and automorphisms.
NEXT STEPS
  • Study the properties of dihedral groups \(D_m\) and their representations.
  • Learn about semi-direct products and how to construct them in group theory.
  • Examine the concept of group actions and their implications for isomorphisms.
  • Explore the automorphism group \(\operatorname{Aut}(N)\) and its role in defining \(\varphi\).
USEFUL FOR

Mathematicians, particularly those specializing in abstract algebra, students studying group theory, and anyone interested in the structural properties of dihedral groups and semi-direct products.

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Homework Statement


Let m ≥ 3. Show that $$D_m \cong \mathbb{Z}_m \rtimes_{\varphi} \mathbb{Z}_2 $$
where $$\varphi_{(1+2\mathbb{Z})}(1+m\mathbb{Z}) = (m-1+m\mathbb{Z})$$

Homework Equations


I have seen most basic concepts of groups except group actions. Si ideally I should not use them for this problem.

The Attempt at a Solution


So I've been thinking about this problem for a couple of days and I just can't seem to arrive to the proof I am looking for.

And so we have that <s> is cyclical of order 2 and <r> is cyclical of order m. Therefore, $$\langle s \rangle \cong \mathbb{Z}_2$$
and $$\langle r \rangle \cong \mathbb{Z}_m$$
I feel I have to use the fact that <r> is normal in Dm and that <r>∩<s> = {e}. I unsure where to go from there

Thanks for the help
 
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I suggest to write it in terms of ##r## and ##s## first, and then see how it translates to ##\mathbb{Z}_m##, resp. ##\mathbb{Z}_2##. And I will write the representatives, aka elements of ##\mathbb{Z}_m## as ##[k] = k+m\mathbb{Z}## which is more convenient and easier to read.

In general a semidirect product ##G = N \rtimes_\varphi H## goes by ##(n_1\, , \,h_1)\cdot (n_2\, , \,h_2) \stackrel{(*)}{=} (n_1 \cdot \varphi(h_1)(n_2)\, , \,h_1\cdot h_2)##, see e.g. https://en.wikipedia.org/wiki/Semidirect_product. We have ##\varphi\, : \,H \longrightarrow \operatorname{Aut}(N)##.

Here we have products ## P =(r^k\; , \;s^\varepsilon)\cdot (r^n\; , \;s^\eta) = r^k\cdot s^\varepsilon \cdot r^n \cdot s^\eta## with ##\varepsilon \in \{\,0,1\,\}##.
Now write ##P## in the form ##P=r^l \cdot s^\mu=(r^l,s^\mu)## and compare that with ##(*)## to see how ##\varphi(s^\varepsilon)(r^n)## has to be defined.
If you're done, you can write this as ##\varphi([\varepsilon])([n])##.

You have only defined ##\varphi([1])([1])##. What are ##\varphi([0])## and ##\varphi([1])([n])## if ##n>1## or short: What is ##\varphi([\varepsilon])## with ##\varepsilon \in \{\,0,1\,\} = \{\,[0],[1]\,\}\,?##
 

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