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Isomorphism under differentiation

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  1. Dec 16, 2014 #1
    Is 《sinx》under differentiation a valid cyclic group.
     
  2. jcsd
  3. Dec 17, 2014 #2

    Stephen Tashi

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    A group must have a binary operation involving it's elements. What are the elements of the group you are asking about? What is the binary operation?

    Perhaps you are thinking that differentiation operates on a set of real valued functions. That is true, but differentiation itself is not a real valued function. (Differentiation is a function from functions to other functions.) So differentiation of a function is not a binary operation involving two real valued functions.
     
  4. Dec 19, 2014 #3
    Consider sin as a row, then differentiation is cyclic, but there is not any connection with groups.
     
  5. Dec 19, 2014 #4

    FactChecker

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    You could consider differentiation operations on the set (sinx, cosx, -sinx, -cosx) where the + operation is consecutive differentiation. With a little work, I am sure you could define a cyclic group.
     
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