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Isosceles triangle with angle bisector

  1. Aug 12, 2016 #1
    1. The problem statement, all variables and given/known data
    Find x

    bandicam 2016-08-12 23-30-16-190.jpg

    2. Relevant equations
    a+b+c=180



    3. The attempt at a solution
    ADB= 65+65+50=180
    How do I find x in DBC?
     
  2. jcsd
  3. Aug 12, 2016 #2

    SammyS

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    What is the measure of angle CBD ?
     
  4. Aug 12, 2016 #3
    ADB=50+65+65=180
    angle bisector -> angle on a line 180 degrees. 180-65=115
    x= 180-115=65, 65/2=32.5
    CBD=32.5+115+32.5

    x=32.5
     
  5. Aug 12, 2016 #4

    SammyS

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    Actually, I asked about angle CBD, ( ∠ CBD ), not triangle CBD ( Δ CBD ).

    Maybe, that's what you mean by
    " angle bisector -> angle on a line 180 degrees. 180-65=115 ",​
    but an angle bisector cuts an angle exactly into two angle of equal measure.

    So, yes, .∠ CBD = 180° - 65° = 115° .

    It's really very confusing, and incorrect, when you state the following.
     
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