Isosceles triangle with angle bisector

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Frank212
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Homework Statement


Find x[/B]
bandicam 2016-08-12 23-30-16-190.jpg


Homework Equations


a+b+c=180[/B]

The Attempt at a Solution


ADB= 65+65+50=180
How do I find x in DBC?
 
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SammyS said:
What is the measure of angle CBD ?
SammyS said:
What is the measure of angle CBD ?

ADB=50+65+65=180
angle bisector -> angle on a line 180 degrees. 180-65=115
x= 180-115=65, 65/2=32.5
CBD=32.5+115+32.5

x=32.5
 
Frank212 said:
ADB=50+65+65=180
angle bisector -> angle on a line 180 degrees. 180-65=115
x= 180-115=65, 65/2=32.5
CBD=32.5+115+32.5

x=32.5
Actually, I asked about angle CBD, ( ∠ CBD ), not triangle CBD ( Δ CBD ).

Maybe, that's what you mean by
" angle bisector -> angle on a line 180 degrees. 180-65=115 ",​
but an angle bisector cuts an angle exactly into two angle of equal measure.

So, yes, .∠ CBD = 180° - 65° = 115° .

It's really very confusing, and incorrect, when you state the following.
Frank212 said:
CBD=32.5+115+32.5