Isothermal expansion of an ideal gas

Click For Summary
SUMMARY

The discussion focuses on the thermodynamic processes involving one mole of a monatomic ideal gas transitioning from an initial state of pressure P and volume V to a final state of pressure 2P and volume 2V. The process includes an isothermal expansion followed by an isochoric compression. Key results established are: the change in energy is 0, the heat input is P x V x ln(2), the work output is also P x V x ln(2), and the change in entropy is R ln(2).

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Knowledge of thermodynamic processes: isothermal and isochoric
  • Familiarity with concepts of internal energy and heat transfer
  • Basic calculus for evaluating integrals in thermodynamic equations
NEXT STEPS
  • Study the derivation of the Ideal Gas Law and its applications
  • Learn about the first law of thermodynamics and its implications for internal energy
  • Explore the concept of entropy and its calculation in various thermodynamic processes
  • Investigate the relationship between pressure, volume, and temperature in isochoric processes
USEFUL FOR

This discussion is beneficial for students of thermodynamics, physics enthusiasts, and professionals in engineering fields who require a solid understanding of gas behavior under varying thermodynamic conditions.

thezac11
Messages
9
Reaction score
0

Homework Statement



One mole of monatomic ideal gas is taken from an initial pressure(P) and volume(V) to a final pressure(2P) and volume(2V). It goes from pressure=P and volume=V to pressure=P/2 and volume=2V through isothermal expansion and from there volume stays constant but the pressure goes to 2P from the previous P/2 and this path is through isochoric compression. The temperature remains constant.

-What is the change in energy of the process?
-What is the heat input?
-What is the work output?
-What is the change in entropy?


Homework Equations



change in energy = (heat in) - (work out)

change in entropy = heat in/temperature

Ideal gas law: PV=nRT, where n=amount of substance, R=constant, T=temp.

The Attempt at a Solution



I know the answers I just want to know how to get them. If you can explain the process I would greatly appreciate it. The final answers are:

-Change in energy = 0

-Heat input = P x V x (ln2)

-Work out = P x V x (ln2)

-Change in entropy = R(ln2)
 
Physics news on Phys.org
thezac11 said:

Homework Statement



One mole of monatomic ideal gas is taken from an initial pressure(P) and volume(V) to a final pressure(2P) and volume(2V). It goes from pressure=P and volume=V to pressure=P/2 and volume=2V through isothermal expansion and from there volume stays constant but the pressure goes to 2P from the previous P/2 and this path is through isochoric compression. The temperature remains constant.

-What is the change in energy of the process?
I am not sure what this question is asking. There are three forms of energy: Work, Heat flow and internal energy.
The change in internal energy
What is the equation for [itex]\Delta U = ?[/itex].(Hint: it involves Cv). What is the Cv for this gas?

Determine the change in U in each step. There is no change in U in the first step (isothermal expansion) but there is a change in internal energy for the second step (isochoric heating). You will have to work out what that is.

-What is the heat input?
In the first step, there is no change in U. So what is the relationship between [itex]\Delta Q[/itex] and W for the first step? In the second step, what is the relationship between P and T if V is constant? If P increases by 4x what happens to T? What amount of heat is required to raise the temperature by that amount (hint: it involves Cv).

-What is the work output?
What is the expression for W in terms of P and change in V? What is the W in the first step? (hint: it involves an integral involving P and V and you have to substitute for P in terms of V and T in that integral) Is there any work done by the gas in the second step (isochoric)?

-What is the change in entropy?
Write out the expression for [itex]\Delta S[/itex] (hint: it involves Q and T and an integral)

What is the heat flow in the first step? What is the temperature? What is [itex]\Delta S[/itex]?

What is the heat flow in the second step? What is the relationship between dQ and dT? Put that into the integral and integrate.

AM
 

Similar threads

Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
9K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 60 ·
3
Replies
60
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K