It says convert (-1, pi/8 ) from polar to rectangular coordinate?

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SUMMARY

The discussion focuses on converting polar coordinates to rectangular coordinates, specifically addressing the points (-1, π/8) and (1, 5π/2). It clarifies that while π/8 is not a special angle on the unit circle, conversion can still be performed using the formulas x = r cos(θ) and y = r sin(θ). The conversation emphasizes that the radius (r) must equal 1 for points to lie on the unit circle, and suggests using calculators or trigonometric identities for angles not typically found on the unit circle.

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  • Understanding of polar coordinates and their representation as (r, θ)
  • Familiarity with trigonometric functions: sine and cosine
  • Knowledge of unit circle properties and special angles
  • Ability to use calculators for evaluating trigonometric functions
NEXT STEPS
  • Learn how to convert polar coordinates to rectangular coordinates using x = r cos(θ) and y = r sin(θ)
  • Study trigonometric identities for angle addition and subtraction
  • Explore the unit circle and its special angles in detail
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Jurrasic
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How do you find these on the unit circle: 5pi/2 ? howabout pi/8 ? Converting from polar to rectangular?
It says convert (-1, pi/8 ) from polar to rectangular coordinate? But there is no pi/8 on the unit circle?
If the'yre on the unit circle just use x=rcosθ and y=rcosθ
another example is for (1, 5pi/2) That doesn't seem to be on the unit circle either. So how can we do these then?
 
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Jurrasic said:
How do you find these on the unit circle: 5pi/2 ? howabout pi/8 ? Converting from polar to rectangular?
It says convert (-1, pi/8 ) from polar to rectangular coordinate? But there is no pi/8 on the unit circle?
If the'yre on the unit circle just use x=rcosθ and y=rcosθ
another example is for (1, 5pi/2) That doesn't seem to be on the unit circle either. So how can we do these then?

-1 is your r and pi/8 is your theta. Like you said use x=rcosθ and y=rcosθ.
 
Dick said:
-1 is your r and pi/8 is your theta. Like you said use x=rcosθ and y=rcosθ.

YOU CAN'T
it won't work unless they're on the unit circle
 
Jurrasic said:
YOU CAN'T
it won't work unless they're on the unit circle

"polar coordinates" means the ordered pair is (r,theta). You want to convert that to (x,y). As long as |r|=1 it is on the unit circle.
 
Dick said:
"polar coordinates" means the ordered pair is (r,theta). You want to convert that to (x,y). As long as |r|=1 it is on the unit circle.

OK how, you keep saying you can do it, so please do, because that's what I'm asking. do it do it do it lol please haha

p.s. the 5pi/2 that's just where pi/2 is, but the pi/8 WHERE is that?
 
Jurrasic said:
YOU CAN'T
it won't work unless they're on the unit circle

Are you saying that since π/8 is not one of the special angles (those related to 30°, 45°, and 60°), the angle is not "on the unit circle"? If that is the case, so what? Either use a calculator to evaluate the necessary trig functions of π/8, or use a trig identity.

For example, if the point is (1, 105°), then in rectangular coordinates it's (cos 105°, sin 105°). Use a calculator and you get (-0.259, 0.966). Or use the fact that 105° = 60° + 45° and evaluate cos (60° + 45°) and sin (60° + 45°). That's it!
 

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