It says convert (-1, pi/8 ) from polar to rectangular coordinate?

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Homework Help Overview

The discussion revolves around converting polar coordinates, specifically the point (-1, π/8), into rectangular coordinates. Participants express confusion regarding the presence of certain angles on the unit circle and the implications for conversion.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the conversion process from polar to rectangular coordinates, questioning the validity of using angles that are not considered "special" angles on the unit circle. There are attempts to clarify the definitions of polar coordinates and the conditions under which conversion is applicable.

Discussion Status

The discussion is active, with participants offering various perspectives on the conversion process. Some express skepticism about converting angles like π/8, while others suggest using calculators or trigonometric identities to evaluate the necessary functions. There is no clear consensus on the approach to take.

Contextual Notes

Participants note that the angles in question, such as π/8 and 5π/2, may not be directly represented on the unit circle, leading to confusion about how to proceed with the conversion. The conversation reflects a mix of assumptions about what constitutes valid angles for conversion.

Jurrasic
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How do you find these on the unit circle: 5pi/2 ? howabout pi/8 ? Converting from polar to rectangular?
It says convert (-1, pi/8 ) from polar to rectangular coordinate? But there is no pi/8 on the unit circle?
If the'yre on the unit circle just use x=rcosθ and y=rcosθ
another example is for (1, 5pi/2) That doesn't seem to be on the unit circle either. So how can we do these then?
 
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Jurrasic said:
How do you find these on the unit circle: 5pi/2 ? howabout pi/8 ? Converting from polar to rectangular?
It says convert (-1, pi/8 ) from polar to rectangular coordinate? But there is no pi/8 on the unit circle?
If the'yre on the unit circle just use x=rcosθ and y=rcosθ
another example is for (1, 5pi/2) That doesn't seem to be on the unit circle either. So how can we do these then?

-1 is your r and pi/8 is your theta. Like you said use x=rcosθ and y=rcosθ.
 
Dick said:
-1 is your r and pi/8 is your theta. Like you said use x=rcosθ and y=rcosθ.

YOU CAN'T
it won't work unless they're on the unit circle
 
Jurrasic said:
YOU CAN'T
it won't work unless they're on the unit circle

"polar coordinates" means the ordered pair is (r,theta). You want to convert that to (x,y). As long as |r|=1 it is on the unit circle.
 
Dick said:
"polar coordinates" means the ordered pair is (r,theta). You want to convert that to (x,y). As long as |r|=1 it is on the unit circle.

OK how, you keep saying you can do it, so please do, because that's what I'm asking. do it do it do it lol please haha

p.s. the 5pi/2 that's just where pi/2 is, but the pi/8 WHERE is that?
 
Jurrasic said:
YOU CAN'T
it won't work unless they're on the unit circle

Are you saying that since π/8 is not one of the special angles (those related to 30°, 45°, and 60°), the angle is not "on the unit circle"? If that is the case, so what? Either use a calculator to evaluate the necessary trig functions of π/8, or use a trig identity.

For example, if the point is (1, 105°), then in rectangular coordinates it's (cos 105°, sin 105°). Use a calculator and you get (-0.259, 0.966). Or use the fact that 105° = 60° + 45° and evaluate cos (60° + 45°) and sin (60° + 45°). That's it!
 

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