Finding the Volume Under a Surface Above a Triangle

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The problem involves finding the volume under the surface defined by z=(y)(x)^2 above a triangle with vertices at (4,0), (1,0), and (2,1). The limits of integration are established as y=0 to y=1 and x=y+1 to x=4-2y. The integrand is correctly identified as (y)(x)^2 dx dy. The original poster seeks confirmation on the accuracy of their setup. The discussion concludes with affirmation that the proposed limits and integrand should work for solving the problem.
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Homework Statement


find the volume under the surface z=(y)(x)^2 and above the triangle with vertices (4,0) (1,0) (2,1)



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The Attempt at a Solution



i got my limits of integration to be y=0 to y=1 and x=y+1 to x=4-2y. my integrand itself is (y)(x)^2dxdy

i just wanted to see if this is correct.
thanks!
 
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help please!
 
nobody ?
 
Mark44 said:
That should work.

^^^ thanks mark
 

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