Iterated maps and eigenvalues and vectors

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SUMMARY

The discussion focuses on solving a two-dimensional linear map defined by the equations Xn+1 = 4Xn - Yn and Yn+1 = -4Xn + 4Yn, with initial conditions X0 = 1 and Y0 = 1. The eigenvalues of the matrix are confirmed as σ1 = 2 and σ2 = 2, with corresponding eigenvectors e1 = (1, 2)T and e2 = (1, -2)T. The solution involves expressing the initial vector v0 = (1, 1) as a linear combination of the eigenvectors of the matrix M, allowing for the explicit calculation of v_n = M^n * v_0.

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franky2727
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totally stuck on this one can't even start to fathom an attempt. first part of the question is show that the eigenvalues of the matrix (2x2 left to right) 4,-1,-4,4 are sigma1=2 and sigma2 =2 and eigenvectors e1= (1,2)T and e2=(1,-2)T done this no problem but am writing this as the second part of the question says

use this result to find the solution to the 2 dimensional linear map

Xn+1 =4Xn -Yn
Yn+1 =-4Xn+4Yn

with X0=1 and y0=1

please help as i have no idea where to even begin. thanks
 
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Call v_n the vector (x_n,y_n) and M your given matrix. Then the iteration is v_n+1=M*v_n. So v_n=M^n*v_0. You'll find this easy to express explicitly if you write v_0=(1,1) as a linear combination of eigenvectors of M.
 

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