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A Jacobian Elliptic Functions as Inverse Elliptic Functions

  1. Apr 4, 2017 #1
    I need help in understanding how Jacobian Elliptic Functions are interpreted as inverses of Elliptic Functions.

    Please reference the wiki page on Jacobian Elliptic functions:


    For example, if $$u=u(φ,m)$$ is defined as $$u(φ,m) = \int_0^φ \frac{1}{ \sqrt{1-m sin^2(θ)}} \, dθ$$

    where ##φ## is the amplitude $$φ=am(u)$$

    Then $$y'=sin(φ)$$ is defined to be the Jacobian function $$sn(u,m)$$ or $$sin(φ)=sn(u,m)$$

    I understand that the Jacobian functions are defined as inverses to the elliptic integrals. Bug where does the ##sin(φ)## come from? I think I am getting getting lost with all of the different variables. Can someone explain in as clearly as possible? Any insight would be appreciated. Thanks!
  2. jcsd
  3. Apr 9, 2017 #2
    The elliptic functions are inverses of the elliptic integrals. Taking the sine of the inverse of the integral is just a convenience. If you're interested, I suggest you experiment with the functions EllipticF and JacobiSN in Mathematica. . If we have the differential equation

    $$y''=g/L\sin(y)$$, then we can solve it exactly using elliptic functions. The solution is:

    $$y(t)=2\arcsin\left\{k\;\text{sn}\left[\sqrt{g/l} (t-t_0),m\right]\right\}$$

    It's a beautiful derivation and I invite anyone interested in non-linear DEs to review the derivation. It can be found in this text which also has a nice chapter on elliptic functions and integrals:

    Last edited: Apr 9, 2017
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