The measurement angles at detectors A and B are
a and
b respectively. Given a known particle polarization angle, once a measurement angle is selected, the corresponding
a' and
b' can be computed. But this is only valid when the particle has a "pure spin state" - that is, it is not entangled.
As a note: during an actual experiment, the measurement angles are commonly selected from three values: roughly -15°, 0°, and +15°.
The final experiment being described involves many measurement with different
a/
b combinations. And each
a and
b is best chosen randomly an instant before the measurement is made.
Here's that sequence:
1) A pair of entangled particles are targeted at two measurement stations.
2) After it is too late to signal the other measurement station, each station randomly picks a measurement angle (
a or
b).
3) The measurements are made.
4) The experiment is repeated at least a few hundred times.
5) Those statistics are consistent with QM predictions, but they confound any attempt to use the "sign λ⋅
a'" model (or any other model using a function of only a λ and the
a's) to explain the result.
jf117 said:
It says a' depends on a and p in a way to be specified. Fine, as it is to be specified, I can live with that until a' is used. But then <σ⋅a> is calculated and the result depends on θ', which is the angle between a' and p. Perhaps knowing how that result (equation (5) in Bell article) is obtained can shed some light on a'.
I have corrected my original post. Vector
a' is an angle between
a and the polarization angle of a "pure" (ie, unentangled) particle. It's an angle computed using equation 5 and the paragraph that precedes equation 5 in Bell's paper.