Jordan Basis for Differential Operator

[fishshoe]

Homework Statement

Let V = P_n(\textbf{F}). Prove the differential operator D is nilpotent and find a Jordan basis.

Homework Equations

D(Ʃ a_k x^k ) = Ʃ k* a_k * x^{k-1}

The Attempt at a Solution

I already did the proof of D being nilpotent, which was easy. But we haven't covered what a "Jordan basis" is in class and it's not in either of my textbooks. I know what Jordan Canonical Form is, and Jordan blocks, but I don't know what a Jordan basis is.

Earlier I did a problem that showed that the matrix form of the differential operator on polynomials of order 2 or less. It was
<br /> \left[<br /> \begin{array}{ c c }<br /> 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 2 \\<br /> 0 &amp; 0 &amp; 0<br /> \end{array} \right]<br />
Is that the kind of basis they're looking for here?

 

[morphism]

No - in a Jordan basis, all entries in the superdiagonal (i.e. the line above the diagonal) have to be either 1 or zero.

 

[fishshoe]

So do I need something like

\begin{array}{ccc}
0 & 1 & 0 & \dots & 0 \\
0 & 0 & 1 & \dots & 0 \\
\dots \\
0 & 0 & 0 & \dots & 1 \\
0 & 0 & 0 & \dots & 0 \end{array}

as an n-vector Jordan basis for the polynomials of order up to n?