Jules: Trying to Remember Calculus Limit

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    Calculus Limit
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SUMMARY

The limit as x approaches 0 of (Cos x - 1)/x is confirmed to be 0. This conclusion is reached through algebraic manipulation and the established limit lim x→0 (sin x)/x = 1. The derivative of cosine at 0, denoted as cos'(0), is calculated as -sin(0), which equals 0, reinforcing the limit's value.

PREREQUISITES
  • Understanding of calculus concepts, specifically limits
  • Familiarity with trigonometric functions, particularly cosine and sine
  • Knowledge of derivatives and their applications
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of limits using L'Hôpital's Rule
  • Explore the properties of trigonometric limits in calculus
  • Learn about the relationship between derivatives and limits
  • Investigate the Taylor series expansion for cosine near 0
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Students of calculus, mathematics educators, and anyone looking to reinforce their understanding of limits and trigonometric functions.

Jules18
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I'm trying to remember a limit I was supposed to have memorized for calc. Is this right?


limx-->0 [Cosx - 1]/x = 0


I know it was something like that, but I'm not sure

Thanks
~Jules~
 
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That's right. You can find the limit by using some algebra and limx→0 sinx/x = 1
 
I call that limit cos'(0)=-sin(0)=0
 

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