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## Homework Statement

In 6th edition of Engineering Mathematics, Programme F2 Intro to Algebra, so far I get it all there, but I'm stumped on one question in the revision excercise, it goes like this:

((2a-3)/4b)+((3a+2)/6b)

## Homework Equations

He then goes on to break down the answers in the back:

A) 2a/4b - 3/4b + 3a/6b +2/6b

then

B) a/2b - 3/4b + a/2b + 1/3b

then

C) a/b - 5/12b

and finally the answer is

D) 1/12b*(12a-5)

## The Attempt at a Solution

I can see how the question is re-written the first time round, and then I get the second part where the first division block is divided by 2, the third by 3 and the 4th by 2. The second one can't be made smaller obviously.

But how he gets (a/b)-(5/12b) and then 1/12b*(12a-5) is above me at the moment, I know it's something really basic that i've missed. Can anyone clarify for me please?

Thanks

Deian