Keep mass vertically still using friction

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SUMMARY

The discussion centers on determining the minimum force required to initiate downward slipping of mass m2, which is suspended above mass m1 on a frictionless surface. The key to solving this problem involves calculating the normal force acting on m2 and expressing the acceleration in terms of relevant parameters. The applied force must overcome the gravitational force acting on m2 to prevent it from slipping. The solution requires a clear understanding of Newton's laws and the dynamics of forces in a two-mass system.

PREREQUISITES
  • Newton's laws of motion
  • Understanding of normal force and gravitational force
  • Basic principles of friction and motion
  • Ability to set up equations of motion for multiple bodies
NEXT STEPS
  • Calculate the normal force acting on mass m2 in a two-body system
  • Derive the expression for acceleration in terms of mass and applied force
  • Explore the effects of varying the mass of m1 and m2 on the system's dynamics
  • Learn about static and kinetic friction coefficients and their applications
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding dynamics and force interactions in multi-body systems.

knc
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A mass m1 is on a frictionless surface. To its right is a second mass m2 not touching the ground, but in the air. An applied force is applied towards the right of both masses. What is the minimum force needed so that the second object JUST starts to slip downwards?

http://i.stack.imgur.com/gQNg8.jpg

I have no idea where to start... I know I need to find the normal force but I have no acceleration.
 
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Write an expression for the acceleration in terms of other parameters.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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