Kernel of linear transformation

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SUMMARY

The discussion focuses on finding the kernel of the linear transformation T: P3 → P2 defined by T(p(x)) = p''(x) + p'(x) + p(0). To determine ker(T), the polynomial p(x) = ax^3 + bx^2 + cx + d must be set to yield a zero polynomial, which requires that all coefficients of the resulting polynomial expression equal zero. The transformation results in a polynomial of the form 6ax + 2b + 3ax^2 + 2bx + c + d, leading to a system of equations to solve for the coefficients a, b, c, and d.

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AndreTheGiant
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Homework Statement



I am having lots of trouble understanding how to get the kernel of linear transformations. I get that you basically set it equal to zero and solve.

T: P3 → P2 given by T(p(x)) = p΄΄(x) + p΄(x) + p(0)

Find ker(T)


The Attempt at a Solution



So P3 = ax^3 + bx^2 + cx +d
then the linear transformation should be

6ax + 2b + 3ax2 + 2bx + c + d


but how do i find ker T?
 
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You've got the transformation right. You want the result to be a zero polynomial. A polynomial is only zero if the coefficient of each power of x is zero.
 

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