Kinematic Particle Homework: Deriving a_r and a_theta

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SUMMARY

The discussion focuses on deriving the radial acceleration (a_r) and tangential acceleration (a_theta) in kinematic particle motion. Participants clarify that the second derivative of the radial position (r) is essential for understanding the relationship between velocity (v) and acceleration (a). It is established that the radial acceleration is a component of total acceleration, and confusion arises regarding the interpretation of the question's requirements for velocity and direction.

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dirk_mec1
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Homework Statement



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Homework Equations


Formulas for a_r and a_theta.

The Attempt at a Solution


I got the second derative of r but I think the fluxie v is a mistake. I am sure that
[itex]\dot{v} =a\[/itex], right?
 
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The statement of the question is rather unclear. If v is the velocity, dv/dt is a vector, but it doesn't ask about the direction. Maybe it means to ask for ##|\dot{\vec v}|##.
The given acceleration appears to be the radial component only, so is not the same as either ##|\dot{\vec v}|## (the total acceleration) or ##\ddot r##.
 
Yes but the radial acceleration is the total acceleration [itex]a =a _r[/itex] so it should be the same right?
 

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