Kinematics - identifying and describing types of motion

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The discussion focuses on verifying the accuracy of a student's homework regarding kinematics, specifically identifying types of motion. The student expresses uncertainty about distinguishing between quicker and slower paces in their description of a truck's journey. Key points include the need for precise terminology, as terms like "quick" and "slow" should be replaced with actual speed measurements. The student's analysis correctly identifies the truck's motion as non-uniform due to changes in velocity and direction, but some explanations are deemed unnecessary. Overall, the feedback emphasizes clarity and accuracy in describing motion and calculating average speed versus average velocity.
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Homework Statement


upload_2016-3-21_22-58-51.png


Homework Equations


average speed = total distance/total time
average velocity = total displacement/total time

The Attempt at a Solution


please verify if my answers are correct. Thanks :D
im specifically having doubts about a), i don't know how to identify when the truck moves at a quicker or slower pace. I've placed a star * beside phrases that i feel are incorrect. Please check them out.
23. [/B]

a)

The truck *quickly moved 14.0 km (South) in 15 min. The truck continued another 6 km at a *slower pace over 10 min, and then stayed at this location for 5 min. The truck moved at a *slower pace and continued on for another 8 km towards the destination, taking 15 min for this portion of its journey.

b)

This motion represents non-uniform motion. This can easily be seen, since there are changes in the slope of the graph. This indicates that there are changes in the truck’s velocity and direction. As the truck picks up and delivers a cargo of cabbage, it will need to make turns on to other roads, change direction to take different routes, slow down at stop signs and traffic lights, and speed up to pass stop signs and traffic lights. In this case, the truck is not maintaining a constant velocity and is changing directions, so it is an example of non-uniform motion.

c)

total time = 25 min

total displacement: d = 14.0 km + 6.0 km = 20 km

average velocity = total displacement / total time

average velocity = 20 km / 25 min

average velocity = 0.8 km /mind)

Total displacement = 8.0 km (S)

t = 25 min

Average velocity = total displacement / total time

Average velocity = 8.0 km (S) / 25 min

Average velocity = 0.32 km/min (S)
 
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alexandria said:
The truck *quickly moved 14.0 km (South) in 15 min. The truck continued another 6 km
You might want to think about that again.
Also, I suggest mentioning constant speed, where appropriate.
 
a) You should not use non-quantified words such as "quick" and "slow". Quote the actual speed.

b) You are here mostly describing a real truck, not the one in the graph, which only moves in one direction. Everything after "As the truck" is superfluous and not part of the solution.

c) This is average speed, not average velocity. Please use correct terminology. You also have not distinguished what you call "total displacement" in c from what you call the same in d!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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