Kinematics Initial Velocity problem

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SUMMARY

The discussion centers on solving a kinematics problem involving a deer and a car. The car, initially traveling at 15.49 m/s, must stop within 10 meters to avoid a collision with a deer that jumps out 40 meters away. The acceleration calculated is approximately 3.0 m/s², derived using the equation Vf² = Vi² + 2AD. Participants confirm that the displacement should be adjusted to 40 meters to find the correct initial velocity.

PREREQUISITES
  • Understanding of kinematic equations, specifically Vf² = Vi² + 2AD
  • Knowledge of basic physics concepts such as velocity, acceleration, and displacement
  • Ability to rearrange equations to solve for unknown variables
  • Familiarity with unit conversions, particularly between mph and m/s
NEXT STEPS
  • Study the derivation and application of kinematic equations in physics
  • Learn how to convert units between miles per hour and meters per second
  • Practice solving similar kinematics problems involving initial and final velocities
  • Explore real-world applications of kinematics in automotive safety and accident analysis
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Students preparing for physics exams, educators teaching kinematics, and anyone interested in understanding motion dynamics in real-world scenarios.

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Homework Statement



A deer jumped out at 40 m in front of a car traveling at 30 mph. If the car managed to stop with 10 m to spare. Determine the velocity at which the car would be traveling so that the collision could not be avoided.


Homework Equations



Vf2=Vi2+2*AD

Vf=Vi+At

S= Vi+0.5*A*t2


The Attempt at a Solution



I have been given a past paper to prepare for an exam. I have the answers which are 3.0 m/s2 for acceleration and the initial velocity =15.49 m/s

I would like some help to work out the initial velocity

I have worked out the acceleration using Vf2=Vi2+2*A*D

Vf=0, Vi=13.41 m/s , D= 30 m

02=13.412+2A*30
02=179.83+2A*30
A= 179,83 / 2*30 = 2.99997 or 3 m/s2

I am wondering do I need to rearrange the equation I have used above to find out the initial velocity or would it be a different equation. Also would I change the displacement to 40 m

Thanks
 
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Same equation, same acceleration, and yes, change displacement to 40 m and solve for the initial velocity.
 

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