Kinematics problem: Determine the velocity of this car during braking

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SUMMARY

The discussion focuses on solving a kinematics problem to determine the velocity of a car during braking. The initial integration of the velocity function resulted in -1.8t³ + t² - 8t + C, with the integration constant C determined to be 30 m/s at t=0s. After recalculating the velocity at t=4s, the corrected function yields a velocity of 1.2 m/s, following the proper derivative of the function. The initial calculation of -101.2 m/s was identified as incorrect due to an error in the integration step.

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Homework Statement
Car starts to brake at t=0s from 30m/s Determine the velocity of the car at 4s and the integration constant
Relevant Equations
a(t)=-0.6t^2+2t-8 (m/s^2)
Step 1. Integrate the function --> it comes out to -1.8t3+t2-8t+c
Step 2. Figure out the integration constant --> I know that the velocity of the car is 30m/s at t=0s so making 30m/s = -1.8(0s)3+(0s)2-8(0s)+C it would seem that C is 30m/s
Step 3. Calculate velocity at 4s --> V(4s)= -1.8(4s)3+(4s)2-8(4s)+30m/s and that equals to -101.2m/s
Am i in the right?
 
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You should have a second look at your first step. What do you get if you take the derivative of your result?
 
allrighty it is wrong it should be -0.2t3...
integration constant does not change but the v(4s) now becomes 1.2m/s
it should be right
 

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