Kinematics question(angular velocity)

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The discussion revolves around calculating the translational speed of a rotating cylinder placed on a flat surface. The initial attempt used the formula v = rω, resulting in a speed of π m/s, which was incorrect as the expected answer is 1.81 m/s. Participants highlight the assumption that energy loss is negligible and discuss the conservation of rotational kinetic energy. The correct approach involves considering both the initial rotational motion and the final state of rolling without slipping. The final angular velocity can be derived from the relationship v = rω, leading to further calculations for accurate results.
mcchoy528

Homework Statement


Question: A circular cylinder with mass of 1 kg and radius a=0.1 m is rotating about its cylindrical axis at a rate of 5 revolutions per second. It is then placed on a flat surface. Assuming that there is no dissipation at contact and the cylinder is rolling without slipping (with negligible rolling friction) on the flat surface, its translational speed is:

Homework Equations


v=rω

The Attempt at a Solution


v=0.1 (5*2π)=π m/s

The answer is 1.81m/s. Can anyone help?
 
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mcchoy528 said:

Homework Statement


Question: A circular cylinder with mass of 1 kg and radius a=0.1 m is rotating about its cylindrical axis at a rate of 5 revolutions per second. It is then placed on a flat surface. Assuming that there is no dissipation at contact and the cylinder is rolling without slipping (with negligible rolling friction) on the flat surface, its translational speed is:

Homework Equations


v=rω

The Attempt at a Solution


v=0.1 (5*2π)=π m/s

The answer is 1.81m/s. Can anyone help?

You've answered a different question. The question you have answered was:

If a cylinder is rolling without slipping at 5 rev/s then what is its translational speed.

That said, I'm not sure what the question is asking. If you put the spinning cylinder on a surface, then there must be energy loss before it gets to a state of rolling without slipping. But, the question seems to ask you to ignore this energy loss. Perhaps try that?
 
mcchoy528 said:
What is wrong with my attempt?

You've assumed that the cylinder has translational speed before it is placed on the surface.
 
how can I answer this question? The rotational kinetic energy is conserved.
1/2mv2=1/2Iω2
If I put the data into this equation, v=2.22m/s . I still can't get the answer.
 
mcchoy528 said:
how can I answer this question? The rotational kinetic energy is conserved.
1/2mv2=1/2Iω2
If I put the data into this equation, v=2.22m/s . I still can't get the answer.

Now you have assumed that the cylinder has stopped rotating and has only translational motion. Note that:

Initially the cylinder is rotating

Finally it is rolling without slipping
 
How can I calculate the final angular velocity? Is the final angular velocity=v/r?
 
Last edited by a moderator:
I think I have got the correct approach.
1/2 I ωi2=1/2mv2+1/2 I ωf2
v=√1/3r2ωi2
 
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