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An electron has a kinetic energy of 5.80 10-17 J. It moves on a circular path that is perpendicular to a uniform magnetic field of magnitude 5.10 10-5 T. Determine the radius of the path?

I know

KE = 1/2mv^2

Using KE = 1/2mv^2 and saying KE = 5.8 x 10^-17, and m = 9.10938 x 10^-31 KG

I get that v= 11284559 m/s

Then using F = mv^2/r, I end up with an answer of 2.27 x 10^-12 m.

It tells me this answer is wrong.

Any help would be great.

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# Homework Help: Kinetic Energy and Magnetic Fields

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