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thoradicus
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Homework Statement
A shell of mass 50kg is fired at 60 degress to the horizontal with a speed of 200 m/s. Neglecting air resistance,calculate the kinetic energy of the shell at the highest point.
Homework Equations
K.E=.5(m)(v)^2
usin(θ)
ucos(θ)
The Attempt at a Solution
My question is shouldn't the K.E of the shell is 0? Since the vertical velocity is zero at the highest point. Should I use horizontal velocty instead? why is that so?
If i use horizontal velocity: 200cos60=100
K.E=(1/2)(50)(100)^2=2.5*10^5