Kinetic Energy in Reference Frames

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SUMMARY

The equation K'sys=1/2MtotalVcm2+1/2μVreli2 represents the total kinetic energy in a reference frame, where Mtotal is the total mass, Vcm is the velocity of the center of mass, and μ is the reduced mass. The first term accounts for the kinetic energy required to conserve momentum in the system, while the second term addresses the kinetic energy that can be converted. Understanding the velocity of the center of mass is crucial, as it is frame-dependent and essential for accurate momentum conservation calculations.

PREREQUISITES
  • Understanding of kinetic energy and momentum conservation principles
  • Familiarity with the concept of center of mass and its velocity
  • Knowledge of reduced mass in physics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the concept of center of mass and its implications in different reference frames
  • Explore the derivation and applications of reduced mass in two-body problems
  • Learn about momentum conservation in elastic and inelastic collisions
  • Investigate alternative methods for calculating kinetic energy in various systems
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Students and professionals in physics, particularly those focusing on mechanics, as well as educators seeking to clarify concepts related to kinetic energy and momentum conservation.

aclark609
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K'sys=1/2MtotalVcm2+1/2[itex]\mu[/itex]Vreli2

I understand this equation represents the total kinetic energy in a reference frame. What I'm not getting out of this is the overall concept. I understand that the first part of the equation is supposed to represent the total kinetic energy required to conserve momentum in the system, but I don't know how.

In other words, how is taking the kinetic energy of the total mass of the system using the center of mass velocity equal to the energy needed to conserve momentum. Why would you use the total mass and the center of mass velocity? Perhaps I need to understand the concept of center of mass velocity a little better and it's purpose.

Same for the second part. Why would you use mu to find the kinetic energy that can be converted? Is it not possible to do it any other way? Perhaps this is the easiest?
 
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aclark609 said:
K'sys=1/2MtotalVcm2+1/2[itex]\mu[/itex]Vreli2

I understand this equation represents the total kinetic energy in a reference frame. What I'm not getting out of this is the overall concept. I understand that the first part of the equation is supposed to represent the total kinetic energy required to conserve momentum in the system, but I don't know how.
How would you do it?

In other words, how is taking the kinetic energy of the total mass of the system using the center of mass velocity equal to the energy needed to conserve momentum. Why would you use the total mass and the center of mass velocity? Perhaps I need to understand the concept of center of mass velocity a little better and it's purpose.
Yes - it is not "center of mass velocity" but "the velocity of the center of mass" and it is frame-dependent.

Same for the second part. Why would you use mu to find the kinetic energy that can be converted? Is it not possible to do it any other way? Perhaps this is the easiest?
It is possible to do it in many different ways. This way distinguishes between different forms the energy takes so it makes the math easier.
 

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