Kinetic energy of a particle help

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SUMMARY

The discussion focuses on calculating the kinetic energy and speed of a particle as it moves between two points, A and B. The particle has a mass of 0.600 kg and a speed of 2.30 m/s at point A, resulting in a kinetic energy of 1.59 J. At point B, the kinetic energy is given as 7.00 J, leading to a calculated speed of 4.83 m/s. The total work done on the particle during its movement from A to B is determined to be 5.41 J.

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  • Basic knowledge of work-energy principle
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  • Ability to solve quadratic equations
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Homework Statement


A 0.600 kg particle has a speed of 2.30 m/s at point A and kinetic energy of 7.00 J at point B.

(a) What is its kinetic energy at A?
(b) What is its speed at B?
(c) What is the total work done on the particle as it moves from A to B?


Homework Equations


J= N*m


The Attempt at a Solution


I am stuck on this problem and don't really know how to go about starting it. I think if i new the first part I could find the other two answers, but I don't know how to do that. Any advice would be appreciated.
 
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What is the formula for kinetic energy?
 
k=.5mv^2

so, k=.5(.6)(2.3^2); k=1.59

b) 7=.5(.6)v^2; v=23.3333^.5; v=4.83

c) (sum)W= kf - ki ; (sum)W= 7-1.59 = 5.41

Thanks,
its been a long day sorry
 
heh. no problem. It looks like you know EXACTLY what you are doing! =)
 

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