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Kinetic energy of a particle help

  1. Feb 24, 2008 #1
    1. The problem statement, all variables and given/known data
    A 0.600 kg particle has a speed of 2.30 m/s at point A and kinetic energy of 7.00 J at point B.

    (a) What is its kinetic energy at A?
    (b) What is its speed at B?
    (c) What is the total work done on the particle as it moves from A to B?


    2. Relevant equations
    J= N*m


    3. The attempt at a solution
    I am stuck on this problem and don't really know how to go about starting it. I think if i new the first part I could find the other two answers, but I don't know how to do that. Any advice would be appreciated.
     
  2. jcsd
  3. Feb 24, 2008 #2

    cepheid

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    What is the formula for kinetic energy?
     
  4. Feb 24, 2008 #3
    k=.5mv^2

    so, k=.5(.6)(2.3^2); k=1.59

    b) 7=.5(.6)v^2; v=23.3333^.5; v=4.83

    c) (sum)W= kf - ki ; (sum)W= 7-1.59 = 5.41

    Thanks,
    its been a long day sorry
     
  5. Feb 24, 2008 #4

    cepheid

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    heh. no problem. It looks like you know EXACTLY what you are doing! =)
     
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