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Kinetic Energy of Electron Beam.

  1. Nov 8, 2012 #1
    1. The problem statement, all variables and given/known data

    Two horizontal plates connected to 600v with the positive at the top.
    A positively charged ion between the plates moves downwards under the
    force of the field (neglect gravity).
    The ion has charge 1.6×10^–19C and mass 2.3×10^–26kg.
    Show that the kinetic energy of the ion is 4.8x10-17 J at the instant
    that it reaches the bottom plate.

    2. Relevant equations

    KE = eV

    3. The attempt at a solution

    eV = 1.6x10^-19 x 600 = 9.6x10^-17 J.

    This is exactly twice the number I am trying to reach and I can't
    get any further. The problem is that I don't understand the significance
    of the ion reaching the bottom plate.

    Thanks.
     
    Last edited: Nov 8, 2012
  2. jcsd
  3. Nov 8, 2012 #2

    collinsmark

    User Avatar
    Homework Helper
    Gold Member

    Hello Minki,

    Welcome to Physics Forums!
    Your calculation of 9.6x10^-17 J looks correct to me if the ion begins accelerating at the positive (top) plate, and the potential difference between the plates is 600 V. (And of course, if we can ignore gravity, and can assume the plates are in a vacuum.)

    Is any information left out of the problem statement? For example is the top plate connected to 600 V and the bottom plate connected to 300 V? Or instead, maybe the ion started accelerating at the midpoint between the plates?

    (The part about the ion reaching the bottom plate is significant because it lets you know the ion's potential energy at the end of the experiment. If you know the difference in potential energy between the beginning and the end of the experiment, you can invoke the work-energy theorem to determine the kinetic energy.)
     
  4. Nov 9, 2012 #3
    That's great Collinsmark. You have answered the question. I did leave out that the ion is midway between the plates.

    Many thanks.
     
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