Kinetic energy of object free fall

Click For Summary

Discussion Overview

The discussion revolves around the kinetic energy of an object in free fall and its relationship with gravitational potential energy. Participants explore the conservation of energy principle and the dependence of kinetic energy on the height from which the object is dropped.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • One participant states that gravitational energy when an object is dropped from height h is E = mgh, while kinetic energy upon impact is E = (1/2)mv^2, suggesting a conservation of energy relationship.
  • Another participant asserts that kinetic energy does depend on height, claiming it is equal to mgh, which is a function of h.
  • There is a repeated inquiry about how height cancels out in the context of kinetic energy.
  • A later reply clarifies that kinetic energy is defined as E_k = (1/2)mv^2, independent of the forces applied, and that if the particle acquires kinetic energy by falling from height h, then the values of mgh and (1/2)mv^2 will be equal, leading to the expression v = √(2gh).

Areas of Agreement / Disagreement

Participants express disagreement regarding the dependence of kinetic energy on height, with some asserting it does depend on height while others argue it does not in the context of the kinetic energy formula.

Contextual Notes

There are unresolved questions regarding the cancellation of height in the equations presented, and the discussion does not clarify the assumptions behind the claims made by participants.

bay
Messages
3
Reaction score
0
If an object is dropped from height, h, then gravitational energy is E = mgh, but kinetic energy when object hits the ground is E=(1/2)mv^2. Conservation of energy states that E(g)=E(k). Why does kinetic energy not depend on height object was dropped?
 
Physics news on Phys.org
It does! Its equal to mgh which is a function of h!
 
Shyan said:
It does! Its equal to mgh which is a function of h!
How does the h cancel out?
 
bay said:
How does the h cancel out?
It doesn't. ## E_k=\frac 1 2 m v^2 ## is the definition of kinetic energy of a particle with mass m and speed v regardless of what forces are applied to it. Any particle with mass m and speed v, has the kinetic energy ## E_k ##. Now if this particle acquired its kinetic energy by falling from a height h under constant gravitational acceleration g, then the numerical value of ## mgh ## and ## \frac 1 2 m v^2 ## will be equal which means the speed of the particle is ## v=\sqrt{2gh} ##.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 77 ·
3
Replies
77
Views
6K
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 54 ·
2
Replies
54
Views
7K
  • · Replies 4 ·
Replies
4
Views
2K