CompuChip said:I don't have the diagram, but I assume that you have some hill given with a downward slope of given angle, and given height.
Well, let's break the problem into two parts.
First, calculate the velocity of the ball at the bottom of the hill (just before it goes airborne). How would you do this?
Then, we can treat the problem as something you have probably seen before, suppose you are standing on a cliff and throw the tennis ball with a velocity v at an angle [itex]\theta[/itex] below the horizontal. How would you find the horizontal distance?
Kinetic energy is the energy an object possesses due to its motion. It is calculated as one-half of the mass of the object multiplied by the square of its velocity.
The kinetic energy of a tennis ball dropped from a specific height will increase as the height increases. This is because the ball gains more potential energy as it is lifted to a greater height, which is then converted into kinetic energy as it falls.
Yes, the weight of the tennis ball does affect its kinetic energy. The heavier the ball, the more kinetic energy it will have when dropped from the same height compared to a lighter ball. This is because the mass of the ball is directly proportional to its kinetic energy.
The surface the tennis ball is dropped on can affect its kinetic energy in two ways. If the surface is soft, such as a foam mat, the ball will compress upon impact and lose some of its kinetic energy. On a hard surface, such as concrete, the ball will have a more elastic collision and retain more of its kinetic energy.
Yes, the shape of the tennis ball can affect its kinetic energy. A ball with a rounder shape will have less air resistance and will therefore have a higher kinetic energy compared to a ball with a less spherical shape. This is because the rounder ball will be able to maintain its velocity for a longer period of time due to less air resistance slowing it down.