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Kinetic Friction and Incline for a Car
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[QUOTE="bartersnarter, post: 5440841, member: 552190"] [h2]Homework Statement [/h2] [ATTACH=full]186884[/ATTACH] [h2]Homework Equations[/h2] [I]friction:[/I][/B] f = μN [B][I]incline angle:[/I][/B] θ = arctan(1/10) [B][I]summation of forces in y:[/I][/B] N - mgcosθ = 0 [B][I]summation of forces in x:[/I][/B] -f - mgsinθ = ma (?) [h2]The Attempt at a Solution[/h2] For this problem, I set the x-axis going up the incline and the y-axis normal to said x-axis. When I drew the FBD, the part that did not make sense to me was the summation of forces in the x-axis. The question wants the car to accelerate UP the incline, but the two forces I draw for the FBD both point down the incline. One of the forces is the x-component of the weight, mgsinθ, and the other is the friction. I know the weight's x-component direction is right, so the wildcard is the friction. Isn't friction opposite to the direction of motion? [/QUOTE]
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Kinetic Friction and Incline for a Car
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