1. A crate resting on a rough horizontal floor is to be moved horizontally. The coefficient of kinetic friction is 0.40. To start the crate moving with the least possible applied force, in what direction should the force be applied? a. Horizontal b. 24 degrees below horizontal c. 22 degrees above the horizontal d. 24 degrees above the horizontal e. 66 degrees below the horizontal Formulas I used. 2. (Normal force) Fn = m*a (Kinetic frictional force) Fk = (uk)*|Fn| (uk being coefficient of kinetic friction) Work I did. 3. Figured out the normal force which was m*a*cos(theta). After I multiplied it by the (uk) and got kinetic frictional force but don't know where to go from there... Thanks in advance!!