Kinetic theory of gases theory question

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Homework Help Overview

The discussion revolves around the kinetic theory of gases, specifically comparing the behavior of oxygen and hydrogen molecules in a mixture at room temperature. Participants are examining the implications of molecular mass on average speed and kinetic energy.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between molecular mass and average speed, questioning how the average kinetic energy relates to the mass of the molecules. Some express confusion about the significance of the term "average" in this context.

Discussion Status

There is an ongoing exploration of the concepts, with some participants providing insights into the relationship between mass and speed. The discussion reflects differing interpretations of the average properties of the gas molecules, but no consensus has been reached.

Contextual Notes

The original poster references the assumption of ideal gas behavior and the need to consider average properties in the context of the problem. There is an acknowledgment of the differences in molecular mass between hydrogen and oxygen.

Mandavi
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Homework Statement


Consider a mixture of oxygen and hydrogen kept at room temperature.As compared to a hydrogen molecule an oxygen molecule hits the wall-
(a) with greater average speed
(b)with smaller average speed
(c)with greater average kinetic energy
(d)with smaller average kinetic energy

Homework Equations


We have to consider both the gases as ideal to get the answer.
Now, for a mixture vrms=(3RT/M)^1/2
where M is average mass of the gases in the mixture and is
M=(n1M1+n2M2)/n1+n2
n denote the number of moles of gases and M their respective molecular masses.
Average kinetic energy for a gas molecule=3/2kT
k=boltzmann constant
T=absolute temperature

The Attempt at a Solution


The answer given is (b)with smaller average speed.Someone please explain the reason for this.
 
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If I understood it right :
both molecules have the same average internal energy, which is kinetic energy
now,the oxygen molecule is heavier than the hydrogen molecule , thus the velocity of the oxygen molecule should be smaller.
mv^2/2 = E
V=(3RT/M)^1/2 when the mass is higher . velocity is lower...
 
Dweirdo said:
If I understood it right :
both molecules have the same average internal energy, which is kinetic energy
now,the oxygen molecule is heavier than the hydrogen molecule , thus the velocity of the oxygen molecule should be smaller.
mv^2/2 = E
V=(3RT/M)^1/2 when the mass is higher . velocity is lower...

Right,but doesn't the word "average" has any significance here?
 
I would rather say Energy per molecule.
the "Average" thing is here because this measures the average velocity ,but it has (if it has) a little effect on the answer. the difference between 2 different types of molecules in this case is big, so you can drop that word.
 
Dweirdo said:
I would rather say Energy per molecule.
the "Average" thing is here because this measures the average velocity ,but it has (if it has) a little effect on the answer. the difference between 2 different types of molecules in this case is big, so you can drop that word.

Okay!Thank you very much!:smile:
 

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