Kinetics in Nromal and Tangential coordinates - SPINING ROD W/ SPOOL

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Homework Help Overview

The discussion revolves around a problem in kinetics involving a spool on an inclined rod, where participants are tasked with determining the maximum speed of the spool to prevent it from slipping. The context includes the mass of the spool, the coefficient of static friction, and the geometry of the setup.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply equations of motion and forces to find the maximum speed, but notes discrepancies with the textbook answer. Participants question the direction of the friction force and suggest revising the equations based on this understanding.

Discussion Status

The discussion is ongoing, with participants actively engaging in clarifying the direction of forces and revising equations. There is no explicit consensus yet, but guidance has been offered regarding the friction force's direction.

Contextual Notes

Participants are working under the constraints of the problem as presented, including the given values for mass, friction, and geometry, while also grappling with the implications of their assumptions on the equations used.

VinnyCee
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Kinetics in Nromal and Tangential coordinates - SPINNING ROD W/ SPOOL

The 2-kg spool fits loosely on the inclined rod for which the coefficient of static friction is [itex]\mu_s\,=\,0.2[/itex]. If the spool is located 0.25 m from A, determine the maximum speed the spool can have so that it does not slip up the rod.

http://img207.imageshack.us/img207/6962/problem13770pa.jpg

Here is what I have for this problem, but it is wrong according to the answer in the text:

[tex]sin\,\theta\,=\,\frac{3}{5}[/tex]

[tex]\theta\,=\,36.9[/tex]

[tex]\sum\,F_x\,=\,N\,cos\,53.1\,-\,f_s\,cos\,36.9\,=\,m\,a_n[/tex]

[tex]\sum\,F_y\,=\,N\,sin\,53.1\,+\,f_s\,sin\,36.9\,-\,m\,g\,=\,m\,a_y[/tex]

[tex]N\,=\,\frac{m\,g}{sin\,53.1\,+\,\mu_s\,sin\,36.9}[/tex]

[tex]N\,=\,21.31\,N[/tex]

Then I use another version of the [itex]F_x[/itex] equation to solve for [itex]v_{max}[/itex]:

[tex]N\,cos53.1\,-\,N\,\mu_s\,cos\,36.9\,=\,m\,\frac{v_{max}^2}{\rho}[/tex]

[tex]v_{max}^2\,=\,\frac{9.39}{10}[/tex]

[tex]v_{max}\,=\,0.969\,\frac{m}{s}[/tex]

The answer is 1.48 in the text though! Any suggestions?
 
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What's the direction of the friction force on the spool?
 
Down the rod towards point A, right?
 
Exactly. Now revise your equations accordingly.
 

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