A particle of mass m falls fom rest; the resistance of the air when the speed is v is kv2 where k is a constant. If s is the distance fallen in time t, prove that s = V2/2g ln(V2/(V2-v2)), where V2=mg/k
The Attempt at a Solution
I have already proven that t = V/2g ln((V+v)/(V-v)). How do I make use of that equation to solve the problem? Do I have to change to v(t) equation and integrate it?